Name of the Board : Madhya Pradesh Board of Secondary Education
Name of the Exam : Class XII
Subject : Chemistry
Document Type : Question Bank
Website : mpbse.nic.in
Download Model/Sample Question Paper : https://www.pdfquestion.in/uploads/mpbse.nic.in/7016-Chemistry11th-Fnl.pdf
Chemistry Sample Question Paper :
Atomic Structure and Chemical Bonding :
Multiple choice question :
The carbon Isotope which was selected for comparing atomic masses by the international union of chemists was–
(a) C14 (b) C50 (c) C12 (d) C70
Related : Madhya Pradesh Board of Secondary Education Class XII Physics Question Bank : www.pdfquestion.in/7015.html
One mole is said to be–
(a) One gram mol (b) 6.023 x 1023 Particles
(c) 6.023 x 10–23 molecule (d) None of these
Molar mass is not–
(a) 1 gram atomicular mass (b) Mass of one mole
(c) 6.023 x 1023 molecular mass (d) 6.023 x 10–23 Atom’s mass
In which compound the oxidation state of oxygen is +2
(a) H2O2 (b) H2O (c) CO2 (d) OF2
The founder of the law of constant proportion was–
(a) John Dalton (b) J.B. Richard (c) Proust (d) Landolt
The law of conservation of mass was given by–
(a) Proust (b) Priestley (c) Landolt (d) Dalton
Relationship between molecular mass and vapour density is–
Balance the chemical equation–
KOH + Cl2 KClO3 + KCl + H2O
Balance the following chemical equation–
Fe2 (SO4)3 + NH3 + H2O Fe(OH)3 + (NH4)2 SO4
The volume of 32 grams of O2 at STP will be–
(a) 16 x 2 CC (b) 2 x 22.4 Litre or 2 x 22400 CC (c) 8 x 22400 CC (d) 32 x 22400 CC
The ratio among the weight of H2 and O2 in H2O will be–
(a) 2:8 (b) 2:16 (c) 2:1 (d) None of these
Atomic mass of Ne is 20.2 a.m.u. then 50.2 gms of Ne will contain atoms–
(a) 6.023 x 1023 (b) 6.023 x 10–23
(c) 1.49 x 1024 (d) None of these
NaCl obtained from different sources was found having ratio by weight among the elements Na and Cl as 23:35.5. Which law is proved by these datas–
In one gm–molecular weight of any substance the number of atoms or molecules present are 6.023 x 1023, this number is called?
The number of atoms or molecules present in one gram–molecular mass of any solid, liquid or a gas will be?
Fill in the blanks. :
19 Cu + 2H2SO4 ………… + ………….. + 2H2O
20 Fe2 (SO4)3 + 6NH3 + 6H2O ………… + …………..
21 NaHCO3 + CH3COOH ………… + …………..
22 2KClO3 MnO2 ………… + …………..
Calculate number of moles in 40 gms of the following given substances–
(a) C6H12O6 (b) CH3OH (c) C2H5OH (d) CH3NH2
(e) CaCO3 (Atomic weight C=12, O=16, H=1, N=14, Ca=40)
On reacting NaOH with NH4Cl. How much amount of NH4Cl will be required to react completely with 25 gms of NaOH–
Through light on the contribution of chemistry in different fields of life.
Explain with the help of suitable example the terms emperical and molecular formulae and the relationship among these two.
(a) C6H12O6 (b) C6H6 (c) Na2CO3 (d) C2H6
Find out the possible empherical formulae for the following molecularformulas and draw a general formula from these empherical formulas for a molecular one.
(a) C6H12O6 (b) C6H6 (c) Na2CO3 (d) C2H6
What are the limitations of a chemical equation what informations it imparts and what are not imported?
Atomic Structure :
Different weights of Isotopes are due to–
(a) Number of electronms and protones are same
(b) Number of protones is less than number of electrones
(c) Number of electrons is less than number of protones
(d) Number of neutrons are different
Which one electronic configuration is not as per Aufbau’s principle–
(a) 1s2, 2s2p (b) [Kr], 4d10, 5s2
In isotopes whose number are same–
(a) Protone and electron (b) Neutron and proton
(c) Nucleon (d) Protone and neutron
The magnetic quantum number is related to–
(a) Magnitude (b) Size (c) Configuration (d) Spin
According to Aufbau principle electrons after 4d, if available will be filled in–
(a) 5f (b) 5p (c) 3d (d) None of these
Electronic configuration of Cr+3 will be–
(a) 1s2, 2s2p6, 3s2p5, d4 (b) 1s2, 2s2p6, 3s2p6d3
(c) 1s2, 2s2p6, 3s2p6, d7 (d) None of these
Electronic configuration of Cl–3 will be–
(a) 1s2, 2s2p6, 3s2p5 (b) 1s2, 2s2p6, 3s2p6d1
(c) 1s2, 2s2p6, 3s2p6 (d) None of these
Na+ ion and Ne element will have same–
(a) Number of electrons (b) Number of protones
(c) Number of neutrons (d) Atomic mass
The value an atom is n=3 and l=2, then value of m will be–
(a) 2 – 1 = 1 & 3 + 2 = 5 (b) +2, +1, ±0, –1, –2
(c) +½ and –½ (d) None of these
For Na+ number of electrons will be–
(a) 11 (b) 10 (c) 12 (d) 23