Organisation : Indian Institute of Technology
Exam : JEE Joint Entrance Examination
Document type : Question Paper
Website : iitjee.org
Download Model/ Sample Question Papers :http://www.iitjee.org/iit-question-papers/iit-papers.html
IIT JEE Sample Question Paper
IIT JEE 2006 Sample Question Paper
Q. 1 Let X be the energy needed to raise the temperature of 5 moles of nitrogen held at constant pressure by one degree.
Let Y be the energy needed to raise 5 moles of carbon monoxide by one degree with the pressure held constant. What is the ratio X:Y?
A. 5:7
B. 1:1
C. 7:5
D. 7:9
Answer : B
Related : FIIT JEE National Talent Search Examination Language Question Paper 2018 : www.pdfquestion.in/29781.html
Description : There is no need to do any calculations here. If you put X on top of Y, you will see that it reduces to the ratio of Cp for nitrogen over Cp for carbon monoxide. And since both gases have the same Cp, the ratio is simply 1:1.
Q. 2 The difference Cp – Cv is a constant. This constant is often called R, the universal gas constant. Which of the following is true given the data?
A. For a monoatomic gas, Cp = 3/2 R
B. For a diatomic gas, Cp = 3/2 R
C. For a monoatomic gas, Cv = 3/2 R
D. For a diatomic gas, Cv = 3/2 R
Answer : C
Description : Helium and argon are monoatomic gases, and we can see that Cv = 3/2 *R = (3/2)*2 = 3.
Q. 3 How much energy would be required to heat two moles of methane by one degree if the gas is kept at constant volume?
A. 6.5 calories
B. 8.5 calories
C. 11 calories
D. 13 calories
Answer : D
Description : The definition of Cv is the amount of energy required to heat one mole of a gas by one degree. Therefore, to heat two moles of methane by one degree will require 2*6.5 = 13 calories.
Q. 4 Which of the following is a possible explanation for the fact that Cp is always greater than Cv?
A. Some of the energy is used to expand the container in order to maintain constant pressure.
B. A rigid container does not conduct heat as well as one that can change shape.
C. There are generally more moles of gas when the pressure is kept constant than when the volume is kept constant.
D. There are generally fewer moles of gas when the pressure is kept constant than when the volume is kep constant.
Answer : A
Description : Because Cp is always greater than Cv we know that it takes more energy to increase a given amount of gas when the pressure is held constant. It is reasonable that the extra energy is used to increase the volume of the container.
Q. 5 A certain amount of energy, X, is sufficient to raise the temperature of 60 moles of argon by T degrees when the pressure is constant. How many moles of argon can be raised by T degrees with the same amount of energy X, if the volume is held constant?
A. 30
B. 50
C. 75
D. 100
Answer : D
Discussion : You can use the two equations
You are given that X = 60*5*T. Let n be the number of moles that can be heated to temperature T with X calories of energy. Then X = n*3*T, and for this equation to be consistent with the previous one, it must be that n = 100.
Q. 6 Which of the following statements accurately reflects the experimental results?
A. There is more DAA in fried potatoes than in raw, uncooked potatoes.
B. There is more AA in fried potatoes than in raw, uncooked potatoes.
C. There is more total vitamin C content in fried than in raw, uncooked potatoes.
D. There is more AA in fried potatoes compared with uncooked potatoes, but only if they are fried at 140oC or lower.
Answer : A
Description : The concentration of DAA in uncooked potatoes is 7.4 mg/100 grams of dry matter. In the four examples of frying, the DAA concentrations ranged from 29.7 to 42.8, clearly indicating an increase.
Q. 7 If some potatoes were boiled in a 10% NaCl solution, and there were 300 grams of potato left, how many milligrams of vitamin C would there be?
A. 14.7
B. 17.4
C. 26.7
D. 44.1
Answer : D
Description : After potatoes are boiled in a 10% NaCl solution, there are 14.7 milligrams of vitamin C per 100 grams of potato. Therefore, if there were 300 grams of potato, there would be 14.7 * 3 = 44.1 milligrams of vitamin C.